Electric heating thermal oil furnaceoverview

For electric heating oil furnaces, heat is generated and transmitted by electric heating elements immersed in the furnace. Using heat transfer oil as the medium, a circulation pump is used to force the heat transfer oil to circulate in the liquid phase, transferring the heat to one or more heating equipment. After unloading from the heating equipment, the heat is returned to the heater through the circulation pump, and then absorbed and transferred to the heating equipment. This process repeats to achieve continuous heat transfer, raising the temperature of the heated object and meeting the heating process requirements.

Safety device for electric heating and thermal oil furnace

1. Conventional electrical protection, leakage protection, short circuit protection, etc.

2. Equipped with multiple interlocking interfaces, it can effectively monitor the oil pump, flow rate, and pressure at any time.

3. There is a set of over temperature alarm system independent of normal temperature control. When the conventional temperature control is out of control due to various reasons, the system can not only alarm in a timely manner, but also turn off the electric heater non resettable to ensure the safe operation of the system. And input the contact signal.

4. The equipment has a reasonable structure, mature technology, complete supporting facilities, short installation cycle, convenient operation and maintenance, safety and reliability, and a wide range of applications.

5. Adopting internal heating closed-loop heating, with high heat utilization rate, significant energy-saving effect, low operating cost, and fast investment recovery.

Heat transfer oil heaterCalculation method for heating power selection

1. Special circumstances require calculation:

A、 Calculate the power of the heater or freezer KW=W × △ t × C × S/860 × T

W=weight of mold or cooling water KG

△ t=the temperature difference between the required temperature and the starting temperature.

C=specific heat oil (0.5), steel (0.11), water (1), plastic (0.45~0.55)

T=time to heat up to the desired temperature (hours)

B、 Request the size of the pump

Need to understand the pump flow rate and pressure (head) required by the customer

P (pressure Kg/cm2)=0.1 × H (head M) × α (specific gravity of heat transfer medium, water=1, oil=0.7-0.9)

L (media required flow rate L/min)=Q (mold required heat Kcal/H)/C (media to hot water ratio=1 oil=0.45) × △ t (temperature difference between circulating media entering and leaving the mold) × α × 60

2. Selection of freezer capacity

A. Q (freezing capacity Kcal/H)=Q1+Q2

Q1 (Heat brought into the mold by raw materials Kcal/H)=W (Weight of raw materials injected into the mold per hour KG) × C × (T1-T2) × S (Safety factor 1.5~2) T1 Temperature of raw materials in the material tube; The temperature at which T2 finished products are taken out of the mold; The heat generated by Q2 hot runner is Kcal/H

B、 Quick calculation method (not applicable with hot runner)

1RT=7~8 OZ 1OZ=28.3g (including safety factor)

1RT=3024Kcal/H=12000BTU/H=3.751KW

1KW=860 Kcal/H 1 Kcal=3.97BTU

3. Cooling tower selection=A+B

A、 Used for injection molding machines

Cooling tower RT=Injector horsepower (HP) x 0.75KW x 860Kcal x 0.4 ÷ 3024

B、 Used for refrigerators

Cooling tower RT=Cold ton of freezer (HP) × 1.25